Title:

Das Gaußsche Eliminationsverfahren

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Protokoll Gauss 2: >ClrScr< Anzahl der zu lösenden Gleichungen:4 >ClrScr< >Koeffizienteneingabe< Sollen die Rechenschritte angezeigt werden (J/N):j >ClrScr< Start-Gleichungen: | (1) 20*x1 + 10*x2 + 3*x3 + 4*x4 = 5 | (2) 3*x1 + 5*x2 + 8*x3 + 2*x4 = 4 | (3) 3*x1 + 5*x2 + 9*x3 + 2*x4 = 8 | (4) 3*x1 + 10*x2 + 13*x3 + 12*x4 = 25 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ I. Vorwärtselimination (2) - 0.15*(1): | (1) 20*x1 + 10*x2 + 3*x3 + 4*x4 = 5 | (2) 0*x1 + 3.5*x2 + 7.55*x3 + 1.4*x4 = 3.25 | (3) 3*x1 + 5*x2 + 9*x3 + 2*x4 = 8 | (4) 3*x1 + 10*x2 + 13*x3 + 12*x4 = 25 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ (3) - 0.15*(1): | (1) 20*x1 + 10*x2 + 3*x3 + 4*x4 = 5 | (2) 0*x1 + 3.5*x2 + 7.55*x3 + 1.4*x4 = 3.25 | (3) 0*x1 + 3.5*x2 + 8.55*x3 + 1.4*x4 = 7.25 | (4) 3*x1 + 10*x2 + 13*x3 + 12*x4 = 25 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ (4) - 0.15*(1): | (1) 20*x1 + 10*x2 + 3*x3 + 4*x4 = 5 | (2) 0*x1 + 3.5*x2 + 7.55*x3 + 1.4*x4 = 3.25 | (3) 0*x1 + 3.5*x2 + 8.55*x3 + 1.4*x4 = 7.25 | (4) 0*x1 + 8.5*x2 + 12.55*x3 + 11.4*x4= 24.25 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ (2) mit (4) vertauscht: | (1) 20*x1 + 10*x2 + 3*x3 + 4*x4 + = 5 | (2) 0*x1 + 8.5*x2 + 12.55*x3 + 11.4*x4 = 24.25 | (3) 0*x1 + 3.5*x2 + 8.55*x3 + 1.4*x4 = 7.25 | (4) 0*x1 + 3.5*x2 + 7.55*x3 + 1.4*x4 = 3.25 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ (3) - 0.411765*(2): | (1) 20*x1 + 10*x2 + 3*x3 + 4*x4 = 5 | (2) 0*x1 + 8.5*x2 + 12.55*x3 + 11.4*x4 = 24.25 | (3) 0*x1 + 0*x2 + 3.38235*x3 + -3.29412*x4 = -2.73529 | (4) 0*x1 + 3.5*x2 + 7.55*x3 + 1.4*x4 = 3.25 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ (4) - 0.411765*(2): | (1) 20*x1 + 10*x2 + 3*x3 + 4*x4 = 5 | (2) 0*x1 + 8.5*x2 + 12.55*x3 + 11.4*x4 = 24.25 | (3) 0*x1 + 0*x2 + 3.38235*x3 + -3.29412*x4 = -2.73529 | (4) 0*x1 + 0*x2 + 2.38235*x3 + -3.29412*x4 = -6.73529 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ (4) - 0.704348*(3): | (1) 20*x1 + 10*x2 + 3*x3 + 4*x4 = 5 | (2) 0*x1 + 8.5*x2 + 12.55*x3 + 11.4*x4 = 24.25 | (3) 0*x1 + 0*x2 + 3.38235*x3 + -3.29412*x4 = -2.73529 | (4) 0*x1 + 0*x2 + 0*x3 + -0.973913*x4 = -4.8087 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ II. Rückwärtseinsetzen | (1) 20*x1 + 10*x2 + 3*x3 + 4*x4 = 5 | (2) 0*x1 + 8.5*x2 + 12.55*x3 + 11.4*x4 = 24.25 | (3) 0*x1 + 0*x2 + 3.38235*x3 + -3.29412*x4 = -2.73529 | (4) x4 = (-4.80870) : -0.973913 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ | (1) 20*x1 + 10*x2 + 3*x3 + 4*x4 = 5 | (2) 0*x1 + 8.5*x2 + 12.55*x3 + 11.4*x4 = 24.25 | (3) x3 = (-2.73529 - -3.29412* 4.9375) : 3.38235 | (4) x4 = 4.9375 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ | (1) 20*x1 + 10*x2 + 3*x3 + 4*x4 = 5 | (2) x2 = ( 24.25 - 12.55* 4 - 11.4* 4.9375) : 8.5 | (3) x3 = 4 | (4) x4 = 4.9375 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ | (1) x1 = ( 5 - 10*-9.675 - 3* 4 - 4* 4.9375) : 20 | (2) x2 = -9.675 | (3) x3 = 4 | (4) x4 = 4.9375 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ | (1) x1 = 3.5 | (2) x2 = -9.675 | (3) x3 = 4 | (4) x4 = 4.9375 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Protokoll Gauss 3: >ClrScr< Anzahl der zu lösenden Gleichungen:3 >ClrScr >Koeffizienteingabe< Sollen die Rechenschritte angezeigt werden (J/N):j >ClrScr< Start-Gleichungen: | (1) 5*x1 + 8*x2 + 10*x3 = 7 | (2) 3*x1 + 5*x2 + 8*x3 = 2 | (3) 10*x1 + 16*x2 + 20*x3 = 4 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ I. Vorwärtselimination II. Rückwärtseinsetzen Die Determinante ist 0 => es existiert keine eindeutige Lösung

  
Stoer/Bulirsch: Numerische Mathematik 1 (Springer-Lehrbuch)
von Roland W. Freund,
Ronald H.W. Hoppe
Siehe auch:
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Numerische Mathematik 2: Eine Einführung - unter...
Analysis 1: Differential- und Integralrechnung e...
Analysis 1: Mit 250 Aufgaben und Lösungen...
Analysis 2 (Springer-Lehrbuch)
 
   
 
     
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